document.write( "Question 324555: 5^2x+1=125^x
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document.write( "My answer
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document.write( "5^2x+1=(5^3)^x
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document.write( "=2x+1+5x
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document.write( "x=1/7 \n" );
document.write( "
Algebra.Com's Answer #232283 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 5^2x+1=125^x \n" ); document.write( "My answer \n" ); document.write( "5^2x+1=(5^3)^x \n" ); document.write( "=2x+1+5x \n" ); document.write( "x=1/7 \n" ); document.write( "--------- \n" ); document.write( "Sub 1/7 for x and check: \n" ); document.write( "5^(2/7 + 1) =? 125^(1/7) \n" ); document.write( "5^(9/7) =? 5^(3/7) \n" ); document.write( "Not equal. \n" ); document.write( "------------ \n" ); document.write( "5^2x+1=125^x \n" ); document.write( "My answer \n" ); document.write( "5^2x+1=(5^3)^x \n" ); document.write( "=2x+1+5x There's nothing on the left of the equal sign??? \n" ); document.write( "x=1/7 \n" ); document.write( "--------- \n" ); document.write( "5^2x+1=125^x \n" ); document.write( "My answer \n" ); document.write( "5^(2x+1)=(5^3)^x \n" ); document.write( "5^(2x+1)=5^3x \n" ); document.write( "2x+1 = 3x \n" ); document.write( "x = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |