document.write( "Question 324555: 5^2x+1=125^x
\n" ); document.write( "My answer
\n" ); document.write( "5^2x+1=(5^3)^x
\n" ); document.write( "=2x+1+5x
\n" ); document.write( "x=1/7
\n" ); document.write( "

Algebra.Com's Answer #232283 by Alan3354(69443)\"\" \"About 
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5^2x+1=125^x
\n" ); document.write( "My answer
\n" ); document.write( "5^2x+1=(5^3)^x
\n" ); document.write( "=2x+1+5x
\n" ); document.write( "x=1/7
\n" ); document.write( "---------
\n" ); document.write( "Sub 1/7 for x and check:
\n" ); document.write( "5^(2/7 + 1) =? 125^(1/7)
\n" ); document.write( "5^(9/7) =? 5^(3/7)
\n" ); document.write( "Not equal.
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\n" ); document.write( "5^2x+1=125^x
\n" ); document.write( "My answer
\n" ); document.write( "5^2x+1=(5^3)^x
\n" ); document.write( "=2x+1+5x There's nothing on the left of the equal sign???
\n" ); document.write( "x=1/7
\n" ); document.write( "---------
\n" ); document.write( "5^2x+1=125^x
\n" ); document.write( "My answer
\n" ); document.write( "5^(2x+1)=(5^3)^x
\n" ); document.write( "5^(2x+1)=5^3x
\n" ); document.write( "2x+1 = 3x
\n" ); document.write( "x = 1\r
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