document.write( "Question 324515: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 miles per hour and train B is traveling at 80 miles per hour. Train A passes a station at 3:25p.m. If train B passes the same station at 3:40p.m., at what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #232282 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Trains A and B are traveling in the same direction on parallel tracks. \n" ); document.write( " Train A is traveling at 60 miles per hour and train B is traveling at 80 miles per hour. \n" ); document.write( " Train A passes a station at 3:25p.m. \n" ); document.write( "If train B passes the same station at 3:40p.m., at what time will train B catch up to train A? \n" ); document.write( ": \n" ); document.write( "from the given information, we know that train B is 15 min (1/4 hr) behind \n" ); document.write( " train A, when train A passes the station \n" ); document.write( ": \n" ); document.write( "The distance between the trains at this time: \n" ); document.write( ": \n" ); document.write( "Let t = time required for train B to catch train A \n" ); document.write( ": \n" ); document.write( "write a distance equation: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "Train B travel dist = Train A travel dist + 20 mi \n" ); document.write( "80t = 60t + 20 \n" ); document.write( "80t - 60t = 20 \n" ); document.write( "20t = 20 \n" ); document.write( "t = 1 hr \n" ); document.write( ": \n" ); document.write( "3:25 + 1 = 4:25 pm, B catches A \n" ); document.write( " |