document.write( "Question 37632: 1o balls numbered 1 to 10 are in a jar. Jack reaches into jar & randomly removes one of the ball. Then jill reaches into the jar & randomlly removes a different ball..What is the probability that the sum of the 2 numbers on the balls removed is even? \n" ); document.write( "
Algebra.Com's Answer #23228 by mszlmb(115)\"\" \"About 
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ok odd+odd=even even+even=even odd+even=odd
\n" ); document.write( "so we're looking at the probability that both picked either odd numbers or that both chose even numbers
\n" ); document.write( "too hard, let's just take the total probability (1) and subtract from it the probability that 1 picked odd and 1 even.
\n" ); document.write( "p(1st guy picking even)or p(1st guy picking odd)=.5
\n" ); document.write( "cuz there's 5/10 even numbers (2,4,6,8,10) and 5/10 odd (1,3,5,7,9)
\n" ); document.write( "p(2nd guy picking odd)or p(2nt guy picking even)=.5
\n" ); document.write( "same reason
\n" ); document.write( "p(2nd guy picking the opposite of 1st guy)=5/10*5/9=5/18=.25252525....
\n" ); document.write( "5/10 cuz 5 of 10 of choices r either even or odd and
\n" ); document.write( "1/9 cuz of those 5/10, 5/9 of the balls remaining were the opposite.
\n" ); document.write( "we times them cuz we have 5/10ths a chance @ first and of those 5/10ths n array of 5/9ths per 5/10ths.
\n" ); document.write( "NOTE had Jack (the 1st dude) put the ball back, p(2nd guy picking opposite of 1st guy) would be 5/10*5/10, but because he takes the ball out, Jill now has a 5/9ths chance to pick a ball opposite his.
\n" ); document.write( "if uv bin keeping up, the answer .25252525... is the probability that the sum of the numbers is not even.
\n" ); document.write( "1-.25252525...=.7474747474.. or .75. 75% chance, .75 probability, 75/100.\r
\n" ); document.write( "\n" ); document.write( "chek and check^2 to c if im right, and plz email me if im wrong.
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