document.write( "Question 324548: 25(x+5)^2 + 4(y-3)^2 = 100
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document.write( "axis to which the major axis is parallel and the center.
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document.write( "I think it may be
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document.write( "x and -5, 3
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document.write( "but i am not sure if i did this correctly
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document.write( "i would appreciate your help \n" );
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Algebra.Com's Answer #232275 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 25(x+5)^2 + 4(y-3)^2 = 100 \n" ); document.write( "Divide thru by 100 to get: \n" ); document.write( "(x+5)^2/4 + (y-3)^2/25 = 1 \n" ); document.write( "----- \n" ); document.write( "The center is (-5,3) \n" ); document.write( "But the major axis has length 2a = 10 \n" ); document.write( "and is parallel to the y-axis. \n" ); document.write( "==================================== \n" ); document.write( "Plot the vertices and you will see that. \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "axis to which the major axis is parallel and the center. \n" ); document.write( "I think it may be \n" ); document.write( "x and -5, 3 \n" ); document.write( " \n" ); document.write( " |