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You can put this solution on YOUR website!
The square root of a number is a number, which, when multiplied by itself, equals that number. For example, the square root of 25 is 5. Why? Because 5*5=25. The square root of 36 is what? 6. Because 6*6=36.\r
\n" ); document.write( "\n" ); document.write( "OK now how do we find square roots?
\n" ); document.write( "Let's look at the number 4096. Too big for now, you say? ... fine...whatever i didn't even like that number :P
\n" ); document.write( "ok fine we'll start with 144 (whiney!) ok
\n" ); document.write( "you put the number 144 on the right
\n" ); document.write( "144. WE know that 144 is divisible by 2... how? Oh oops I forgot to show you the table! here it is. this table explains how you know if a number is evenly divisible by one of these numbers:
\n" ); document.write( "1: all numbers are divisible by 1
\n" ); document.write( "2: number must end with an even digit (12,14,199948576 would work, 12.4,3,1 won't)
\n" ); document.write( "3: sum of digits of number add up to something divisible by 3 (ie 33,342 sum of digits is 3+3+3+4+2=15 1+5=6 so 33,342 is divisible by 3)
\n" ); document.write( "4: if the TENS digit is odd (1,3,5,7,9), then the ONES digit must be 2 or 6. and if the TENS digit is even (0,2,4,6,8) the ONES digit must be 0,4,8. (ie: 1124 has 10's dgt 2, even and 1's dgt 4. according 2 the rules it is evenly divisible; the answer is 1124/4=881)
\n" ); document.write( "5: 1's dgt is 0 or 5.
\n" ); document.write( "6: 1's digit is even and sum is divisible by 3
\n" ); document.write( "7: find one!
\n" ); document.write( "8: if 10's digit is 0, 8, or 4; 1's digit must be 8. if 10's digit is 1 or 9, 1's dgt must b 6. if 10's dgt is 2 or 6, 1's dgt must b 4. if 10's dgt is 3 or 7, 1's dgt must equal 2. if 10's dgt is 5 or 8, 10's dgt must b 0. if 10's dgt is 9, 1's is 0 or 8. if there is an odd number in the 100's place, add 4 to all sums unless there is an odd number in the thousands etc. o jeez this is nuts haha i'll organize it sum other day
\n" ); document.write( "9: sum divisible by 9
\n" ); document.write( "10: ends in 0.\r
\n" ); document.write( "\n" ); document.write( "OK that was exasporating; now
\n" ); document.write( "take 144/2=72/2=36/2=18/2=9/3=3/3=1
\n" ); document.write( "ok so we have 2*2*2*2*3*3
\n" ); document.write( "cross out one of each, because we are square rooting, and we have 2*2*3. the answer: 12. yea
\n" ); document.write( "to know how to square root any number, like 2, extensive research must be done on the equation of sqare rooting. its hard but probably worth it or somthin
\n" ); document.write( "wen they didn't have calculators, they memorized many square roots!
\n" ); document.write( "ok so now, the big #, 4096.
\n" ); document.write( "4096/2=2048/2=1024/2=512/2=256/2=128/2=64/2=32/2=16/2=8/2=4/2=2/2=1
\n" ); document.write( "ok so we have 2*2*2*2*2*2*2*2*2*2*2*2 cut out half
\n" ); document.write( "2*2*2*2*2*2=4*4*4=16*4=64
\n" ); document.write( "c that wasn't so hard the square root of 4096 is 64.\r
\n" ); document.write( "\n" ); document.write( "we've only just scratched the ice of an iceberg, IM me if u need more help. \n" ); document.write( "