document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324458>Question 324458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for: 25^(2x-1) = 5^(5x+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232225 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite 25 s 5^2.\r<BR>\n" );
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document.write( "(5^2)^(2x - 1) = 5^(5x + 1)\r<BR>\n" );
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document.write( "5^(4x - 2) = 5^(5x + 1)\r<BR>\n" );
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document.write( "Since we now have the same base 5 on both sides, we simply bring down the exponents and solve for x.\r<BR>\n" );
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document.write( "4x - 2 = 5x + 1\r<BR>\n" );
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document.write( "Can you find x now? </SPAN>\n" );
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