document.write( "Question 4822: what is the solution of x+y=4 and 2x-y=-5 \n" ); document.write( "
Algebra.Com's Answer #2322 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! This problem is perfect for the substitution method:\r \n" ); document.write( "\n" ); document.write( "Rewrite x + y = 4 as \n" ); document.write( "y = 4-x by subtracting x from both sides of the equation.\r \n" ); document.write( "\n" ); document.write( "then use this (4-x) in the second equation for y: \n" ); document.write( "2x-y=-5 as \n" ); document.write( "2x-(4-x)=-5\r \n" ); document.write( "\n" ); document.write( "Clear the parentheses: \n" ); document.write( "2x-4+x=-5\r \n" ); document.write( "\n" ); document.write( "Combine like terms: \n" ); document.write( "3x-4=-5\r \n" ); document.write( "\n" ); document.write( "3x-4+4=-5+4 \n" ); document.write( "3x=-1\r \n" ); document.write( "\n" ); document.write( "Divide both sides by 3 to isolate the variable: \n" ); document.write( "x=-1/3\r \n" ); document.write( "\n" ); document.write( "By putting the x value back into either equation: \n" ); document.write( "-1/3+y=4 \n" ); document.write( "y=4 2/3\r \n" ); document.write( "\n" ); document.write( "After putting both x and y into the equations to verify the results: \n" ); document.write( "-1/3 + 4 1/3 = 4 \n" ); document.write( "2(-1/3)-4 1/3 = -5\r \n" ); document.write( "\n" ); document.write( "The solution set is: \n" ); document.write( "(-1/3,4 1/3) \n" ); document.write( " \n" ); document.write( " |