document.write( "Question 324369: The tens digit of a two digit number is 3 more than the units digit. The number is 8 times more than 6 times the sum of the digits. Find the number. (possible sums are 85, 74, 52, 41) \n" ); document.write( "
Algebra.Com's Answer #232156 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
\"10x%2By=z\" where xy is the 2 digit number
\n" ); document.write( "\"8%286%28x%2By%29%29=z\"
\n" ); document.write( "\"y%2B3=x\"\r
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\n" ); document.write( "well possibles would be
\n" ); document.write( "96, 9+6=15, 15*6=90, 90*8
\n" ); document.write( "85, 8+5=13, 13*6=78, 78*8
\n" ); document.write( "74, 7+4=11, 11*6=66, 66*8
\n" ); document.write( "63, 6+3=9, 9*6=54, 54*8
\n" ); document.write( "52, 5+2=7, 7*6=42, 42*8
\n" ); document.write( "41, 4+1=5, 5*6=35, 35*8
\n" ); document.write( "30, 3+0=3, 3*6=18, 18*8=144 all above are also more than 2 digits so this problem is unsolvable unless the problem was not written correctly.
\n" ); document.write( "8times more than 6 times the sum of x and y means 8(6(x+y))=48(x+y)\r
\n" ); document.write( "\n" ); document.write( "id suggest rereading original question or discus this problem with the teacher/professor\r
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