document.write( "Question 324354: six years ago i was three times as old as my brother and now i am twice as old; find our present ages? \n" ); document.write( "
Algebra.Com's Answer #232149 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let brother's age = x \n" ); document.write( "my age = 2x \n" ); document.write( ".. \n" ); document.write( "6 years ago our ages were: \n" ); document.write( "brother - x-6 \n" ); document.write( "myself 2x-6 \n" ); document.write( ".. \n" ); document.write( "I was 3 time his age then \n" ); document.write( "2x-6 = 3(x-6) \n" ); document.write( "2x-6 = 3x-18 \n" ); document.write( "3x-2x=18-6 \n" ); document.write( "x=12 years brother's age \n" ); document.write( "My age now = 24 years.\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "Your feedback is very valuable for improving the solution. \n" ); document.write( " \n" ); document.write( " |