document.write( "Question 324354: six years ago i was three times as old as my brother and now i am twice as old; find our present ages? \n" ); document.write( "
Algebra.Com's Answer #232149 by mananth(16946)\"\" \"About 
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let brother's age = x
\n" ); document.write( "my age = 2x
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\n" ); document.write( "6 years ago our ages were:
\n" ); document.write( "brother - x-6
\n" ); document.write( "myself 2x-6
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\n" ); document.write( "I was 3 time his age then
\n" ); document.write( "2x-6 = 3(x-6)
\n" ); document.write( "2x-6 = 3x-18
\n" ); document.write( "3x-2x=18-6
\n" ); document.write( "x=12 years brother's age
\n" ); document.write( "My age now = 24 years.\r
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