document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324356>Question 324356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages of father and son is 55 years.after 16 years the father will be twice as old as his son, what are their present ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232145 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the age of son be x<BR>\n" );
document.write( "father's age = 55-x<BR>\n" );
document.write( "..\r<BR>\n" );
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document.write( "after 16 years their ages will be:<BR>\n" );
document.write( "son x+16<BR>\n" );
document.write( "father 55-x+16= 71-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Father's age = twice son's age<BR>\n" );
document.write( "71-x= 2(x+16)<BR>\n" );
document.write( "71-x = 2x +32<BR>\n" );
document.write( "3x= 71-32<BR>\n" );
document.write( "3x=39<BR>\n" );
document.write( "x=13 years , son's age<BR>\n" );
document.write( "Father's age = 55-x<BR>\n" );
document.write( "= 55-13<BR>\n" );
document.write( "=42 years\r<BR>\n" );
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document.write( "Your feedback is very important for improving the solution </SPAN>\n" );
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