document.write( "Question 324334: the average life of a brand of automobile tires is 30,000 miles with a standard deviation of 2,000 miles. If a Tire is randomly selected and tested find the probability that it will have a life span between 25,000 and 28,000 miles. Assome the variable is normally distributed \n" ); document.write( "
Algebra.Com's Answer #232129 by Fombitz(32388)\"\" \"About 
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Find the z scores for 25000 and 28000.
\n" ); document.write( "\"z1=%28x-mu%29%2Fsigma=%2825000-30000%29%2F2000=-2.5\"
\n" ); document.write( "\"z2=%28x-mu%29%2Fsigma=%2828000-30000%29%2F2000=-1.0\"
\n" ); document.write( "Find the corresponding P(z).
\n" ); document.write( "\"P%28z1%29=0.00621\"
\n" ); document.write( "\"P%28z2%29=0.15866\"
\n" ); document.write( "Subtract the probabilities to find the probability for the range,
\n" ); document.write( "(\"25000%3C=x%3C=28000\")
\n" ); document.write( "\"P%28x%29=0.15866-0.00621=0.1524\"
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