document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37614>Question 37614</A>: <I><SPAN STYLE=\"word-break: break-all;\">  400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.\r<BR>\n" );
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document.write( "Answer:   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23212 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Amanda has 400 feet of lumber to frame a<BR>\n" );
document.write( "rectangular patio (the perimeter of a rectangle is 2<BR>\n" );
document.write( "times length plus 2 times width). She wants to<BR>\n" );
document.write( "maximize the area of her patio (area of a rectangle is<BR>\n" );
document.write( "length times width). What should the dimensions of the<BR>\n" );
document.write( "patio be, and show how the maximum area of the patio<BR>\n" );
document.write( "is calculated from the algebraic equation.<BR>\n" );
document.write( "Answer:<BR>\n" );
document.write( "IF L AND B ARE DIMENSIONS WE HAVE<BR>\n" );
document.write( "PERIMETER=2(L+B)=400.....OR.....L+B=200..OR......B=200-L.................I<BR>\n" );
document.write( "AREA=A<BR>\n" );
document.write( "=LB=L(200-L)=200L-L^2=-{L^2-200L}=-{(L^2)-2(L)(100)+100^2-100^2}<BR>\n" );
document.write( "A=10000-(L-100)^2<BR>\n" );
document.write( "(L-100)^2 BEING PERFECT SQUARE,ITS MINIMUM VALUE IS<BR>\n" );
document.write( "ZERO.<BR>\n" );
document.write( "HENCE AREA IS MAXIMUM WHEN L-100 IS ZERO,OR WHEN L=100<BR>\n" );
document.write( "AND THEN THE MAXIMUM AREA WOULD BE<BR>\n" );
document.write( "A-MAX.=10000-0=10000<BR>\n" );
document.write( "DIMENSIONS ARE 100*100 </SPAN>\n" );
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