document.write( "Question 324295: use formulat: sample mean+ margin of error...margin of error=z o/sqrtn
\n" );
document.write( " ___
\n" );
document.write( "a manager of a baseball satdium wished to construct a 90% confidence interval for the average age of all baseball fans. in a random sample of 40 fans the mean age was 32.5 wiht a standard deviation of 2.3 years. construct an internval. why would the mananger fin this informatio useful?\r
\n" );
document.write( "\n" );
document.write( "i cam up with the margin error of .60....is that all i need to do for this problem or do i do the phat+.60 and phat-.60...or am i adding many extra steps that aren't necessary.....help please thank you \n" );
document.write( "
Algebra.Com's Answer #232110 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a manager of a baseball satdium wished to construct a 90% confidence interval for the average age of all baseball fans. in a random sample of 40 fans the mean age was 32.5 wiht a standard deviation of 2.3 years. construct an internval. why would the mananger fin this informatio useful? \n" ); document.write( "i cam up with the margin error of .60....is that all i need to do for this problem or do i do the phat+.60 and phat-.60...or am i adding many extra steps that aren't necessary \n" ); document.write( "================ \n" ); document.write( "For this confidence interval you need: \n" ); document.write( "x-bar = 32.5 \n" ); document.write( "and \n" ); document.write( "margin of error = 1.6849*2.3/sqrt(40) = 0.6127 \n" ); document.write( "----- \n" ); document.write( "Then construct xbar-ME < u < xbar+ME \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |