document.write( "Question 324261: 1 number is twice another number, if the sum of their reciprocal is 1/4 find the 2 numbers \n" ); document.write( "
Algebra.Com's Answer #232099 by MathTherapy(10552)\"\" \"About 
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1 number is twice another number, if the sum of their reciprocal is 1/4 find the 2 numbers\r
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\n" ); document.write( "\n" ); document.write( "Let the smaller number be S\r
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\n" ); document.write( "\n" ); document.write( "Then the larger number is 2S, since one number is twice the other\r
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\n" ); document.write( "\n" ); document.write( "Reciprocal of the smaller number, or S is \"1%2FS\", and the reciprocal of the larger number is \"1%2F%282S%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since the reciprocals sum to \"1%2F4\", then we'll have: \"1%2FS+%2B+1%2F%282S%29+=+1%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Multiplying by LCD, 4S, we have: 4 + 2 = S. So S, or the smaller number is \"highlight_green%286%29\", and the larger number is \"highlight_green%2812%29\" (6*2).\r
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\n" ); document.write( "\n" ); document.write( "Smaller #: 6 ; Larger #: 12\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F6+%2B+1%2F12+=+1%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%2F12+%2B+1%2F12+=+1%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F12+=+1%2F4\" (TRUE)
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