document.write( "Question 324283: At maximum speed an airplane travels 2,460 miles against the wind in 6 hours. Flying with the wind the plane can travel the same distance in 5 hours. What is the speed of the plane with no wind? \n" ); document.write( "

Algebra.Com's Answer #232092 by mananth(16946) $\"\"$ $\"About$

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let speed of wind be y mph
\n" ); document.write( "let speed of plane in still air be x
\n" ); document.write( "..
\n" ); document.write( "Against wind the speed = x-y
\n" ); document.write( "distance traveled = 2460
\n" ); document.write( "2460/x-y= 6
\n" ); document.write( "6x-6y= 2460
\n" ); document.write( "x-y=410...........1
\n" ); document.write( "..
\n" ); document.write( "with wind speed = x+y
\n" ); document.write( "distance is same 2460
\n" ); document.write( "2460/x+y=5
\n" ); document.write( "5x+5y=2460
\n" ); document.write( "x+y=492............2
\n" ); document.write( "..
\n" ); document.write( "Add equation 1 & 2
\n" ); document.write( "x-y+x+y=410+492
\n" ); document.write( "2x=902
\n" ); document.write( "x= 451 mph speed of plane in still air.
\n" ); document.write( "..
\n" ); document.write( "Plug the value of x in equation 1
\n" ); document.write( "451-y=410
\n" ); document.write( "y=451-410
\n" ); document.write( "y=40 mph the speed of wind
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "Your feed back about the solution is very important in improvement. \n" ); document.write( "

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