document.write( "Question 324169: A building 150ft tall cast a 50ft long shadow. If a person looks down from the top of the building, what is the measure of th angle of depression from the top of the building to the end of the shadow (to the nearest degree)? (Assume the person's eyes are level with the top of the building.)\r
\n" );
document.write( "\n" );
document.write( "Thanks for taking the time to look at this. \n" );
document.write( "
Algebra.Com's Answer #232065 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A building 150ft tall cast a 50ft long shadow. \n" ); document.write( " If a person looks down from the top of the building, what is the measure of the \n" ); document.write( " angle of depression from the top of the building to the end of the shadow \n" ); document.write( " (to the nearest degree)? (Assume the person's eyes are level with the top of the building.) \n" ); document.write( ": \n" ); document.write( "A right triangle is formed by the 150 ft building, 50 ft shadow and the line \n" ); document.write( " of sight to the end of the shadow \n" ); document.write( ": \n" ); document.write( "We can use the tangent of the upper angle (a) \n" ); document.write( "tan(a) = \n" ); document.write( "a = 18.435 degrees \n" ); document.write( ": \n" ); document.write( "Find the angle of depression: \n" ); document.write( "90 - 18.435 = 72 degrees\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |