document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324219>Question 324219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 2 numbers is -1. ( X + Y = -1 ) Five times the first number equals 3 times the second number. Find the 2 numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232053 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=-1 <BR>\n" );
document.write( "5X=3Y OR X=3Y/5<BR>\n" );
document.write( "3Y/5+Y=-1<BR>\n" );
document.write( "(3Y+5Y)/5=-1<BR>\n" );
document.write( "8Y/5=-1<BR>\n" );
document.write( "8Y=-5<BR>\n" );
document.write( "Y=-5/8 AMS.<BR>\n" );
document.write( "X=3(-5/ 8)/5<BR>\n" );
document.write( "X=(-15/8)/5<BR>\n" );
document.write( "X=-15/8*1/5<BR>\n" );
document.write( "X=-3/8<BR>\n" );
document.write( "X=-3/8 ANS. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );