document.write( "Question 324112: Mike made an extra $8000 last year from a part time job. He invested part of the money at 10% and the rest at 7%. He made a total of $710 in interest. How much was invested at 7%? \n" ); document.write( "
Algebra.Com's Answer #232003 by galactus(183)\"\" \"About 
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Let x=amount invested at 7%. Then, the amount invested at 10% would be 8000-x.\r
\n" ); document.write( "\n" ); document.write( "So, we have \".07x%2B.10%288000-x%29=710\"\r
\n" ); document.write( "\n" ); document.write( "\".07x%2B800-.10x=710\"\r
\n" ); document.write( "\n" ); document.write( "\"-.03x=-90\"\r
\n" ); document.write( "\n" ); document.write( "\"x=3000\" invested at 7%, there is 5000 invested at 10%.
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