document.write( "Question 324040: The perimeter of a rectangle is 146 inches. The length exceeds the width by 29 inches. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #231939 by msgmhenderson(11)![]() ![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle is 146 inches. The length exceeds the width by 29 inches. Find the length and the width. \n" ); document.write( "perimeter formula for rectangle is 2W * 2L where W represent width and L represent length \n" ); document.write( "We know that the length is L + 29 for one side so 2 sides is 2(L + 29) \n" ); document.write( "and the width is W so for 2 sides is 2W \n" ); document.write( "2 (L + 29) + 2W = 146 \n" ); document.write( "2L +(2)*(29) + 2W = 146 \n" ); document.write( "2L + 58 +2W = 146 \n" ); document.write( "2L + 2W = 146 - 58 \n" ); document.write( "2L + 2W = 88 \n" ); document.write( "88/4 WHICH IS THE FOUR SIDES \n" ); document.write( "22 IS WIDTH \n" ); document.write( "22 + 29 IS LENGTH \n" ); document.write( "51 IS LENGTH \n" ); document.write( " |