document.write( "Question 323999: Find the standard form of the equation of the line passing through (5, - ⅔)
\n" ); document.write( "and perpendicular to the graph of x = 3y.
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Algebra.Com's Answer #231920 by Fombitz(32388)\"\" \"About 
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\"x+=+3y\"
\n" ); document.write( "\"y=%281%2F3%29x\"
\n" ); document.write( "The slope of this line is \"m=1%2F3\"
\n" ); document.write( "Perpendicular lines have slopes that are negative reciprocals.
\n" ); document.write( "\"m1%2Am2=-1\"
\n" ); document.write( "\"m2=-1%2Fm1=-3\"
\n" ); document.write( "Use the slope-intercept form of a line \"y=mx%2Bb\"
\n" ); document.write( "\"y=-3x%2Bb\"
\n" ); document.write( "Use the point (5,-2/3) to solve for b.
\n" ); document.write( "\"-2%2F3=-3%285%29%2Bb\"
\n" ); document.write( "\"b=-2%2F3%2B45%2F3\"
\n" ); document.write( "\"b=43%2F3\"
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\n" ); document.write( "\"y=-3x%2B43%2F3\"
\n" ); document.write( "\"3y=-9x%2B43\"
\n" ); document.write( "\"highlight%289x%2B3y=43%29\"
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