document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37431>Question 37431</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant has coffee beans that sell for $9 per<BR>\n" );
document.write( "pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be<BR>\n" );
document.write( "used in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23192 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = number of pounds of $9 coffee.<BR>\n" );
document.write( "The 100 - x = number of pounds of $12 coffee.<BR>\n" );
document.write( "Then we write the \"cost\" equation:<BR>\n" );
document.write( "9x + 12(100 - x) = (11.25)(100)<BR>\n" );
document.write( "9x + 1200 - 12x = 1125<BR>\n" );
document.write( "-3x = -75<BR>\n" );
document.write( "x = 25<BR>\n" );
document.write( "Thus 25 lbs of $9 and 75 lbs of $12 coffee. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );