document.write( "Question 324063: Please help\r
\n" ); document.write( "\n" ); document.write( "An experimental egg farm is raising chickens to produce low cholesterol eggs. A lab tested 25 randomly selected eggs and found that the mean amount of cholesterol was 190 mg. The sample standard deviation was found to be s = 18.0 mg on this group. Assume that the population is normally distributed. \r
\n" ); document.write( "\n" ); document.write( "a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest tenths. \r
\n" ); document.write( "\n" ); document.write( "b.Find a 95% confidence interval for the mean  cholesterol content for all experimental eggs. Assume that the population is normally distributed.
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Algebra.Com's Answer #231917 by stanbon(75887)\"\" \"About 
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An experimental egg farm is raising chickens to produce low cholesterol eggs. A lab tested 25 randomly selected eggs and found that the mean amount of cholesterol was 190 mg. The sample standard deviation was found to be s = 18.0 mg on this group. Assume that the population is normally distributed.
\n" ); document.write( "a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest tenths.
\n" ); document.write( "ME = ts/sqrt(n)
\n" ); document.write( "t for 0.975 with df = 24 = 2.0639
\n" ); document.write( "s = 18
\n" ); document.write( "n = 25
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\n" ); document.write( "ME = 2.0639*18/sqrt(25) = 7.43
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\n" ); document.write( "b.Find a 95% confidence interval for the mean  cholesterol content for all experimental eggs. Assume that the population is normally distributed.
\n" ); document.write( "95$ CI: 190-7.43 < u < 190+7.43
\n" ); document.write( "182.47 < u < 197.43
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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