document.write( "Question 324054: A college student earned $5100 during summer break. He invested all the money. Part of the money he invested at 8% and the rest at 6%. He earned a total of $362.00 in interest. How much did he invest at 8% and how much did he invest at 6%? \n" ); document.write( "
Algebra.Com's Answer #231912 by stanbon(75887)\"\" \"About 
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A college student earned $5100 during summer break. He invested all the money. Part of the money he invested at 8% and the rest at 6%. He earned a total of $362.00 in interest. How much did he invest at 8% and how much did he invest at 6%?
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\n" ); document.write( "Quantity Eq: x + y = 5100
\n" ); document.write( "Interest Eq:0.08x + 0.06y = 362
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\n" ); document.write( "Multiply thru the 1st by 8
\n" ); document.write( "Multiply thru the 2nd by 100
\n" ); document.write( "8x + 8y = 8*5100
\n" ); document.write( "8x + 6y = 36200
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\n" ); document.write( "Subtract the 2nd from the 1st and solve for \"y\":
\n" ); document.write( "2y = 4600
\n" ); document.write( "y = $2300 (amt. invested at 6%
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\n" ); document.write( "Since x+y = 5100, x = 5100-2300 = $2800 (amt. invested at 8%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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