document.write( "Question 324020: Find all solutions for the equation. Record your answers in exact form where possible.
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\n" ); document.write( "2 cos ^2 x = -3sin x\r
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Algebra.Com's Answer #231902 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "First thing to do is remember that \r
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\n" ); document.write( "\n" ); document.write( "and then a little re-arranging:\r
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\n" ); document.write( "\n" ); document.write( "Next, let , so:\r
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\n" ); document.write( "\n" ); document.write( "which factors rather tidily:\r
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\n" ); document.write( "\n" ); document.write( "Hence\r
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\n" ); document.write( "\n" ); document.write( "But recall that . Since the range of is , we must exclude . Therefore:\r
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\n" ); document.write( "\n" ); document.write( "Finally,\r
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\n" ); document.write( "\n" ); document.write( "Looking at the unit circle and remembering that sin is the -coordinate of a point on the unit circle,\r
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\n" ); document.write( "\n" ); document.write( "(see http://en.wikipedia.org/wiki/Unit_circle)\r
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\n" ); document.write( "\n" ); document.write( "You see that there are two possibilities, or . However, the instructions for the problem say to find all solutions and does not give a range, hence we need to allow for the periodicity of the sine function. Therefore the final answer is:\r
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