document.write( "Question 323983: The height in feet of an object thrown upward is given by the equation h = 12t + 9 – ½t2, where h is the height of the object after t seconds. \r
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\n" ); document.write( "\n" ); document.write( "What is the height after ½ second?\r
\n" ); document.write( "\n" ); document.write( "At what time does it reach its maximum height?\r
\n" ); document.write( "\n" ); document.write( "What is the maximum height?
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Algebra.Com's Answer #231877 by Alan3354(69443)\"\" \"About 
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The height in feet of an object thrown upward is given by the equation h = 12t + 9 – ½t2, where h is the height of the object after t seconds.
\n" ); document.write( "What is the initial position?
\n" ); document.write( "What is the height after ½ second?
\n" ); document.write( "At what time does it reach its maximum height?
\n" ); document.write( "What is the maximum height?
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\n" ); document.write( "h = 12t + 9 – ½t2 A strange function, but could be true on a different planet.
\n" ); document.write( "\"h%28t%29+=+-%281%2F2%29t%5E2+%2B+12t+%2B+9\"
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\n" ); document.write( "What is the initial position?
\n" ); document.write( "@ t=0: h(t) = 9 (no units were specified, 9 something)
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\n" ); document.write( "What is the height after ½ second?
\n" ); document.write( "\"h%281%2F2%29+=+-%281%2F2%29%2A%281%2F4%29+%2B+6+%2B+9+=+14.875\"
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\n" ); document.write( "At what time does it reach its maximum height?
\n" ); document.write( "At the vertex of the parabola, t = -b/2a
\n" ); document.write( "t = -12/(-1) = 12 seconds
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\n" ); document.write( "What is the maximum height?
\n" ); document.write( "h(12) = (-1/2)*144 + 12*12 + 9
\n" ); document.write( "h(12) = 81
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