document.write( "Question 323983: The height in feet of an object thrown upward is given by the equation h = 12t + 9 – ½t2, where h is the height of the object after t seconds. \r
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document.write( "What is the initial position? \r
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document.write( "What is the height after ½ second?\r
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document.write( "At what time does it reach its maximum height?\r
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document.write( "What is the maximum height?
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Algebra.Com's Answer #231877 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The height in feet of an object thrown upward is given by the equation h = 12t + 9 – ½t2, where h is the height of the object after t seconds. \n" ); document.write( "What is the initial position? \n" ); document.write( "What is the height after ½ second? \n" ); document.write( "At what time does it reach its maximum height? \n" ); document.write( "What is the maximum height? \n" ); document.write( "-------------------------- \n" ); document.write( "h = 12t + 9 – ½t2 A strange function, but could be true on a different planet. \n" ); document.write( " \n" ); document.write( "----------------------------------- \n" ); document.write( "What is the initial position? \n" ); document.write( "@ t=0: h(t) = 9 (no units were specified, 9 something) \n" ); document.write( "--------------------- \n" ); document.write( "What is the height after ½ second? \n" ); document.write( " \n" ); document.write( "------------------------------------------- \n" ); document.write( "At what time does it reach its maximum height? \n" ); document.write( "At the vertex of the parabola, t = -b/2a \n" ); document.write( "t = -12/(-1) = 12 seconds \n" ); document.write( "--------------------------- \n" ); document.write( "What is the maximum height? \n" ); document.write( "h(12) = (-1/2)*144 + 12*12 + 9 \n" ); document.write( "h(12) = 81 \n" ); document.write( " \n" ); document.write( " |