document.write( "Question 323957: Mary is presently twice as old as Maggy. Ten years ago, Maggy's age was one-third of Mary's then. Ten years from now, Maggy's age will be three-fifths of Mary's age then. How old is each? \n" ); document.write( "
Algebra.Com's Answer #231875 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let Maggy's age = x \n" ); document.write( "Mary's age = 2x \n" ); document.write( ".. \n" ); document.write( "ten years later their ages will be \n" ); document.write( "Maggie= x+10 \n" ); document.write( "Mary = 2x+10 \n" ); document.write( ".. \n" ); document.write( "x+10 = 3/5 (2x+10) \n" ); document.write( "5(x+10)=3(2x+10) \n" ); document.write( "5x+50=6x+30 \n" ); document.write( "6x-5x=50-30 \n" ); document.write( "x=20 years Maggie's age \n" ); document.write( "Mary's age = 2x = 40 years \n" ); document.write( " |