document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323963>Question 323963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)A card is drawn at random from an ordinary pack of 52 playing cards.Find the probability of finding a)an ace b)a six or a heart c)neither a nine or a spade\r<BR>\n" );
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document.write( "2)Two cards are drawn at random from an ordinary pack of 52 playing cards.Find the probability(P) that one is a diamond and the other is a heart\r<BR>\n" );
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document.write( "please give me the answers by tomorrow as it very urgent...... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231841 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1a) 4 aces in 52 cards, P(ace)=4/52=1/13<BR>\n" );
document.write( "1b) P(6)=4/52, P(heart)=13/52, P(6 of hearts)=1/52<BR>\n" );
document.write( "P(6 or heart)=P(6)+P(heart)-P(6 of hearts)=4/52+13/52-1/52=16/52=4/13<BR>\n" );
document.write( "1c) P(9)=4/52, P(spade)=13/52, P(9 of spades)=1/52<BR>\n" );
document.write( "P(9 or spade)=4/13<BR>\n" );
document.write( "P(not 9 or spade)=1-4/13=9/13<BR>\n" );
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document.write( "2) I assume you mean they are drawn without replacement.<BR>\n" );
document.write( "P(diamond)=4/52=1/13<BR>\n" );
document.write( "P(heart)=4/51<BR>\n" );
document.write( "P(diamond, heart)=(1/13)(4/51)=4/663 </SPAN>\n" );
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