document.write( "Question 323209: (k-3)/(k-2)-(k-4)/(k-1)=(3k+2)/(k^2-3k+2) \n" ); document.write( "

Algebra.Com's Answer #231828 by Fombitz(32388) $\"\"$ $\"About$

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\n" ); document.write( "Use the common denominator $\"k%5E2-3k%2B2=%28k-2%29%28k-1%29\"$
\n" ); document.write( " $\"%28k-3%29%2F%28k-2%29-%28k-4%29%2F%28k-1%29=%283k%2B2%29%2F%28k%5E2-3k%2B2%29\"$
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\n" ); document.write( "Multiply both sides by $\"%28%28k-2%29%28k-1%29%29\"$
\n" ); document.write( " $\"k%5E2-4k%2B3-k%5E2%2B6k-8=3k%2B2\"$
\n" ); document.write( " $\"2k-5=3k%2B2\"$
\n" ); document.write( " $\"highlight%28k=-7%29\"$
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