document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323940>Question 323940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> using the five-step problem-solving process<BR>\n" );
document.write( "A rancher outside Houston decides to build a silo inside his corral. The rectangular corral measures 23 m by 17 m and the silo's base is circular with a diameter of x meters. Find a polynomial for the remaining area of the corral (in square meters) after the silo is built.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231823 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length of corral = 23 m<BR>\n" );
document.write( "width of corral = 17m<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area of Corral = 17*23 = 391 m^2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "diameter of silo = x<BR>\n" );
document.write( "radius = x/2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area of circle = pi*r^2<BR>\n" );
document.write( "Area = pi*(x/2)^2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area of corral - area of silo = area of remaining area <BR>\n" );
document.write( "391- pi*(x/2)^2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );