document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37491>Question 37491</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please solve and show all work. Thank you so much!!! \r<BR>\n" );
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document.write( "(a/4a +15) - 3 = -2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23182 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From a /(4a +15) - 3 = -2, we add three to both sides first...<BR>\n" );
document.write( "a /(4a +15) = 1<BR>\n" );
document.write( "The cross multiply giving us<BR>\n" );
document.write( "a = 4a + 15<BR>\n" );
document.write( "Now subtract 4a from both sides and get<BR>\n" );
document.write( "-3a = 15<BR>\n" );
document.write( "and divide by -3 to get<BR>\n" );
document.write( "a = -5 </SPAN>\n" );
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