document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323902>Question 323902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the equation of the line perpendicular to the line joining (4, 2) and (3, -5) and passing through (4, 2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231807 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4,2 ) (3, -5)\r<BR>\n" );
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document.write( "slope of the line joining them is<BR>\n" );
document.write( "m= y2-y1/x2-x1<BR>\n" );
document.write( "m=-5-2 / 3-4<BR>\n" );
document.write( "=-7/-1<BR>\n" );
document.write( "m=7\r<BR>\n" );
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document.write( "so the general equation is y=7x+b<BR>\n" );
document.write( "plug the value of any one poin to get the value of b<BR>\n" );
document.write( "2=28+b<BR>\n" );
document.write( "b=-26\r<BR>\n" );
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document.write( "The line perpendicular to it will have slope o -1/7\r<BR>\n" );
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document.write( "The equation for that lineis  y= -1/7 x -26<BR>\n" );
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