document.write( "Question 323889: the Length of a rectangle is four times its width. If the area of the rectangle is 324 yd^2, find its perimeter \n" ); document.write( "
Algebra.Com's Answer #231785 by nyc_function(2741)\"\" \"About 
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Length = 4x\r
\n" ); document.write( "\n" ); document.write( "Width = x\r
\n" ); document.write( "\n" ); document.write( "Area = 324\r
\n" ); document.write( "\n" ); document.write( "324 = (4x)(x)\r
\n" ); document.write( "\n" ); document.write( "324 = 4x^2\r
\n" ); document.write( "\n" ); document.write( "324/4 = x^2\r
\n" ); document.write( "\n" ); document.write( "81 = x^2\r
\n" ); document.write( "\n" ); document.write( "sqrt[81] = sqrt[x^2]\r
\n" ); document.write( "\n" ); document.write( "9 = x\r
\n" ); document.write( "\n" ); document.write( "We find the perimter using P = 2L + 2W.\r
\n" ); document.write( "\n" ); document.write( "P = 2(4x) + 2(x)\r
\n" ); document.write( "\n" ); document.write( "P = 2(4*9) + 2(9)\r
\n" ); document.write( "\n" ); document.write( "P = 2(36) + 18\r
\n" ); document.write( "\n" ); document.write( "P = 72 + 18\r
\n" ); document.write( "\n" ); document.write( "P = 90 yards
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