document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37558>Question 37558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me figure out this problem.<BR>\n" );
document.write( "4y/y^2+6y+5 + 2y/y^2-1\r<BR>\n" );
document.write( "\n" );
document.write( "I keep coming up with 2y^2/6y+5<BR>\n" );
document.write( "Is this right, should it be broken down more?  <BR>\n" );
document.write( "I appreciate your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23177 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from 4y/(y^2+6y+5) + 2y/(y^2-1),  we can find the lowest common denominator (after factoring both denoms.) as (y + 5)(y + 1)(y - 1)...then we'll need to convert each fraction to that denominator...so we have<BR>\n" );
document.write( "4y/(y^2+6y+5) + 2y/(y^2-1) = <BR>\n" );
document.write( "4y(y - 1)/[(y + 5)(y + 1)(y - 1)] + 2y(y + 5)/[(y + 5)(y + 1)(y - 1)] =<BR>\n" );
document.write( "and expanding and combining the numerator's terms, we get<BR>\n" );
document.write( "(4y^2 - 4y + 2y^2 + 10y) / [(y + 5)(y + 1)(y - 1)] =<BR>\n" );
document.write( "(6y^2 + 6y) / [(y + 5)(y + 1)(y - 1)] =<BR>\n" );
document.write( "6y(y + 1) / [(y + 5)(y + 1)(y - 1)] =<BR>\n" );
document.write( "notice here the (y + 1)'s cancel...<BR>\n" );
document.write( "6y / [(y + 5)(y - 1)]<BR>\n" );
document.write( "and we're done... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );