document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323720>Question 323720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 26 m. The length is 7 m more than twice the width. Find the dimensions \r<BR>\n" );
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document.write( "Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231661 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's have x be the width. The length will be 2x+7. Now we can set up the equation as:<BR>\n" );
document.write( "x+x+(2x+7)+(2x+7)=26<BR>\n" );
document.write( "Now combine like terms:<BR>\n" );
document.write( "6x+14=26<BR>\n" );
document.write( "Subtract 14 and divide 4 into both sides to get:<BR>\n" );
document.write( "x=2 meters for the width and <BR>\n" );
document.write( "11 meters for the length<BR>\n" );
document.write( "Got it?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com<BR>\n" );
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