document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37543>Question 37543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mat around a picture measures x inches across. The length of the picture with its mat is 40 inches, and the width of the picture with its mat is 24 inched. If the area of the picture is 192 square inches, find the dimensions of the picture. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23162 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here the setup for this is <BR>\n" );
document.write( "(40 - 2x)(24 - 2x) = 192<BR>\n" );
document.write( "4x^2 - 128x + 960 = 192<BR>\n" );
document.write( "4x^2 - 128x + 768 = 0<BR>\n" );
document.write( "x^2 - 32x + 192 = 0<BR>\n" );
document.write( "(x - 8)(x - 24) = 0<BR>\n" );
document.write( "x = 8 or x = 24<BR>\n" );
document.write( "but x = 24 is extraneous, x = 8<BR>\n" );
document.write( "Therefore the dimensions of the original picture are<BR>\n" );
document.write( "(40 - 16) by (24 - 16) or<BR>\n" );
document.write( "24 in x 8 in </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );