document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37437>Question 37437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for n.\r<BR>\n" );
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document.write( "2log n-log (n-1)= log4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23161 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From 2log n - log (n-1) = log4, we apply the laws of logarithms to get<BR>\n" );
document.write( "log [(n^2) / (n - 1)] = log 4<BR>\n" );
document.write( "Thus we can exponentiate both sides and get<BR>\n" );
document.write( "(n^2) / (n - 1) = 4<BR>\n" );
document.write( "Now cross multiply and solve for n...<BR>\n" );
document.write( "n^2 = 4(n - 1)<BR>\n" );
document.write( "n^2 = 4n - 4<BR>\n" );
document.write( "n^2 - 4n + 4 = 0<BR>\n" );
document.write( "(n - 2)^2 = 0<BR>\n" );
document.write( "and<BR>\n" );
document.write( "n = 2 </SPAN>\n" );
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