document.write( "Question 323498: an airplane covers a distance of 1500 miles in three hours when it flies with the wind and 31/3 hours when it flies against the wind. what is the speed of the plane in still air? \n" ); document.write( "
Algebra.Com's Answer #231573 by Fombitz(32388)\"\" \"About 
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Let P be the plane speed in still air, W be the wind speed.
\n" ); document.write( "Rate*Time=Distance
\n" ); document.write( "\"%28P%2BW%293=1500\"
\n" ); document.write( "1.\"P%2BW=500\"
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\n" ); document.write( "\"%28P-W%29%2810%2F3%29=1500\"
\n" ); document.write( "2.\"P-W=450\"
\n" ); document.write( "Add eq. 1 and eq. 2 to eliminate W.
\n" ); document.write( "\"P%2BW%2BP-W=500%2B450\"
\n" ); document.write( "\"2P=950\"
\n" ); document.write( "\"P=475\"mph
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\n" ); document.write( "Then use either equation to solve for W.
\n" ); document.write( "\"475%2BW=500\"
\n" ); document.write( "\"W=25\"mph
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