document.write( "Question 323561: what is the area of an isosceles right triangle with hypotenuse 6 square root of 2
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Algebra.Com's Answer #231535 by mananth(16946)\"\" \"About 
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let side be x
\n" ); document.write( "x^2+x^2= 6sqrt2
\n" ); document.write( "2x^2= 6sqrt2
\n" ); document.write( "x^2= 6/2 sqrt2
\n" ); document.write( "x^2=3sqrt2
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\n" ); document.write( "Area of triange = 1/2* base * height
\n" ); document.write( "Area = 1/2 * x*x ( isoscles triangle)
\n" ); document.write( "area = 1/2 x^2
\n" ); document.write( "plug the value of x^2
\n" ); document.write( "area = 1/2* 3 sqrt2
\n" ); document.write( "area = 3/ sqrt2\r
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