document.write( "Question 323585: A chemist has two different solutions. One has 50% alcohol and 50% water and the other has 75% alcohol and 25% water. How many liters of each should be mixed to obtain 8 liters of solution comprised of 60% alcohol and 40% water? \n" ); document.write( "
Algebra.Com's Answer #231530 by mananth(16946)![]() ![]() You can put this solution on YOUR website! One has 50% alcohol and 50% water \n" ); document.write( "other has 75% alcohol and 25% water. \n" ); document.write( "Mixture = 8 liters of solution 60% alcohol and 40% water? \n" ); document.write( ".. \n" ); document.write( "let 50% alcohol required be x liters \n" ); document.write( "75% acohol required will be 8-x liters \n" ); document.write( "Total mixture = 8 liters 60% \n" ); document.write( ".. \n" ); document.write( "0.5x+0.75(8-x)=8*0.6 \n" ); document.write( "0.5x+6-0.75x=4.8 \n" ); document.write( "-0.25x=-1.2 \n" ); document.write( "x= -1.2/ -0.25 \n" ); document.write( "x=4.8 liters 50% alcohol \n" ); document.write( "75% alcohol required = 3.2 liters \n" ); document.write( " |