document.write( "Question 323585: A chemist has two different solutions. One has 50% alcohol and 50% water and the other has 75% alcohol and 25% water. How many liters of each should be mixed to obtain 8 liters of solution comprised of 60% alcohol and 40% water? \n" ); document.write( "
Algebra.Com's Answer #231530 by mananth(16946)\"\" \"About 
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One has 50% alcohol and 50% water
\n" ); document.write( "other has 75% alcohol and 25% water.
\n" ); document.write( "Mixture = 8 liters of solution 60% alcohol and 40% water?
\n" ); document.write( "..
\n" ); document.write( "let 50% alcohol required be x liters
\n" ); document.write( "75% acohol required will be 8-x liters
\n" ); document.write( "Total mixture = 8 liters 60%
\n" ); document.write( "..
\n" ); document.write( "0.5x+0.75(8-x)=8*0.6
\n" ); document.write( "0.5x+6-0.75x=4.8
\n" ); document.write( "-0.25x=-1.2
\n" ); document.write( "x= -1.2/ -0.25
\n" ); document.write( "x=4.8 liters 50% alcohol
\n" ); document.write( "75% alcohol required = 3.2 liters
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