document.write( "Question 323520: A projectile is launched at an approximately 60-degree angle to the horizontal with an initial speed of 256 ft/sec. The equation for its vertical distance from the ground is h = 222t – 16t2, where t is time in seconds. Find the projectile’s maximum height and the total time that it is in the air. \n" ); document.write( "
Algebra.Com's Answer #231512 by ankor@dixie-net.com(22740)\"\" \"About 
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A projectile is launched at an approximately 60-degree angle to the horizontal
\n" ); document.write( " with an initial speed of 256 ft/sec.
\n" ); document.write( "The equation for its vertical distance from the ground is h = 222t – 16t^2,
\n" ); document.write( "where t is time in seconds.
\n" ); document.write( "Find the projectile’s maximum height and the total time that it is in the air.
\n" ); document.write( ":
\n" ); document.write( "Find the axis symmetry of the equation h = -16t^2 + 222t
\n" ); document.write( "t = \"%28-222%29%2F%282%2A-16%29\"
\n" ); document.write( "t = \"%28-222%29%2F%28-32%29\"
\n" ); document.write( "t = 6.9375 second for max height
\n" ); document.write( "Find the max height
\n" ); document.write( "h = -16(6.9375^2) + 222(6.9375)
\n" ); document.write( "h = -16(48.1289) + 1540.125
\n" ); document.write( "h = -770.0624 + 1540.125
\n" ); document.write( "h = +770.0625 ft max height
\n" ); document.write( ":
\n" ); document.write( "Total time in the air is when it hits the ground, then h=0
\n" ); document.write( "-16t^2 + 222t = 0
\n" ); document.write( "Divide equation by -16t
\n" ); document.write( "t - 13.875 = 0
\n" ); document.write( "t = 13.875 sec in the air
\n" ); document.write( " \n" ); document.write( "
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