document.write( "Question 37537: Can i Have a answere for the following two questions, thanks very much\r
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\n" ); document.write( "\n" ); document.write( "1) 0.04^log(base 0.2)3\r
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Algebra.Com's Answer #23150 by AnlytcPhil(1810)\"\" \"About 
You can put this solution on YOUR website!
1) 0.04^log(base 0.2)3 \r\n" );
document.write( "2) 10^1+ln5\r\n" );
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document.write( "0.04log0.23 \r\n" );
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document.write( "0.04 can be written in terms of the base 0.2, that is,\r\n" );
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document.write( "0.04 = (0.2)˛\r\n" );
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document.write( "So substitute (0.2)˛ for 0.04\r\n" );
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document.write( "[(0.2)˛]log0.23\r\n" );
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document.write( "Remove the brackets by multiplying the exponents 2 and log0.23\r\n" );
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document.write( "(0.2)2·log0.23\r\n" );
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document.write( "Use this rule of logarithms in the exponent:   A·logBC = logBCA\r\n" );
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document.write( "(0.2)log0.23˛  \r\n" );
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document.write( "Substitute 9 for 3˛\r\n" );
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document.write( "(0.2)log0.29\r\n" );
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document.write( "Use this rule of logarithms:  BlogBA = A\r\n" );
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document.write( "Answer: 9\r\n" );
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document.write( "2) 101+ln5\r\n" );
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document.write( "You can't simplify that, so I'd just punch it into a calculator\r\n" );
document.write( "and give the decimal value\r\n" );
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document.write( "                406.8533651\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com

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