document.write( "Question 323432: Michael drove to a friend`s house a rate of 40 mph. he came back by the same route, but at a rate of 45 mph. if the round-trip took 4 hours what is the distance to his friend`s house? \n" ); document.write( "
Algebra.Com's Answer #231483 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=40T FIRST TRIP \n" ); document.write( "D=45(4-T) RETURN TRIP \n" ); document.write( "THE DISTANCES ARE THE SAME TEREFORE THE EQUATIONS ARE THE SAME. \n" ); document.write( "40T=45(4-T) \n" ); document.write( "40T=180-45T \n" ); document.write( "40t+45T=180 \n" ); document.write( "85T=180 \n" ); document.write( "T=180/85 \n" ); document.write( "T=2.118 HRS. FOR THE FIRST TRIP. \n" ); document.write( "4-2.118=1.88 HRS. FOR THE RETURN TRIP. \n" ); document.write( "PROOF: \n" ); document.write( "40*2.118=45*1.88 \n" ); document.write( "84.7~84.7 \n" ); document.write( "2*84.7=169.4 MILES IS THE DISTANCE OF THE ROUND TRIP. \n" ); document.write( " |