document.write( "Question 323432: Michael drove to a friend`s house a rate of 40 mph. he came back by the same route, but at a rate of 45 mph. if the round-trip took 4 hours what is the distance to his friend`s house? \n" ); document.write( "
Algebra.Com's Answer #231483 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "D=40T FIRST TRIP
\n" ); document.write( "D=45(4-T) RETURN TRIP
\n" ); document.write( "THE DISTANCES ARE THE SAME TEREFORE THE EQUATIONS ARE THE SAME.
\n" ); document.write( "40T=45(4-T)
\n" ); document.write( "40T=180-45T
\n" ); document.write( "40t+45T=180
\n" ); document.write( "85T=180
\n" ); document.write( "T=180/85
\n" ); document.write( "T=2.118 HRS. FOR THE FIRST TRIP.
\n" ); document.write( "4-2.118=1.88 HRS. FOR THE RETURN TRIP.
\n" ); document.write( "PROOF:
\n" ); document.write( "40*2.118=45*1.88
\n" ); document.write( "84.7~84.7
\n" ); document.write( "2*84.7=169.4 MILES IS THE DISTANCE OF THE ROUND TRIP.
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