document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37469>Question 37469</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Time to swing. The period T (time in seconds for one complete cycle) of a simple pendulum is related to the length L (in feet) of the pendulum by the formula 8T^2 = pie^2L. If a chld is on a swing with a 10 foot chain, then how long does it take to complete one cycle of the swing? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23148 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay...we plug 10 in for L and find T...<BR>\n" );
document.write( "8(T^2) = (pi^2)L<BR>\n" );
document.write( "T^2 = (pi^2)(10) / 8<BR>\n" );
document.write( "T^2 = 12.3245 and<BR>\n" );
document.write( "T = 3.51 sec </SPAN>\n" );
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