document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=323460>Question 323460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 mph and train B is traveling at 50mph. Train A passes a station at 4:20a.m. If train B passes the same station at 4:32a.m., at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #231462 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=231462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do it like this one.<BR>\n" );
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document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is going 100 miles per hour, Train B is going 110 miles per hour. Train A passes a station at 12:25am. Train B passes that same station at 12:55am. At what time will Train B catch up to Train A?<BR>\n" );
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document.write( "In 1/2 hour (1255-1225) train A goes 50 miles (100 * 1/2).<BR>\n" );
document.write( "Train B gains on train A at 10 mph (110 - 100).<BR>\n" );
document.write( "50/10 = 5 hours.<BR>\n" );
document.write( "1255 + 500 = 5:55AM<BR>\n" );
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