document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37534>Question 37534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Condense the expression. 3log(base 10)2-log(base 10)y+1/3log(base 10)x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23142 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay...using the laws of logs, we have<BR>\n" );
document.write( "3log 2 - log y + 1/3log x =<BR>\n" );
document.write( "log(2^3) - log y + log (x^1/3) =<BR>\n" );
document.write( "log(8) - log y + log (x^1/3) =<BR>\n" );
document.write( "[log(8) + log (x^1/3)] - log y =<BR>\n" );
document.write( "log [8x^(1/3) / y] </SPAN>\n" );
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