document.write( "Question 323301: The height in feet of a projectile with an initial velocity of 160 feet per second and an initial height of 55 feet is a function of time t, in seconds, given by h(t)= -16t^2+160t+55. Find the maximum height of the projectile.\r
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Algebra.Com's Answer #231418 by nerdybill(7384)\"\" \"About 
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The height in feet of a projectile with an initial velocity of 160 feet per second and an initial height of 55 feet is a function of time t, in seconds, given by h(t)= -16t^2+160t+55. Find the maximum height of the projectile.
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\n" ); document.write( "Finding the vertex will give you the max height
\n" ); document.write( "h(t)= -16t^2+160t+55
\n" ); document.write( "axis of symmetry:
\n" ); document.write( "t = -b/(2a)
\n" ); document.write( "t = -160/(2(-16))
\n" ); document.write( "t = -160/(-32)
\n" ); document.write( "t = 5 sec
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\n" ); document.write( "So, height is:
\n" ); document.write( "h(t)= -16t^2+160t+55
\n" ); document.write( "h(5)= -16(5)^2+160(5)+55
\n" ); document.write( "h(5) = -16(25)+800+55
\n" ); document.write( "h(5) = -400+800+55
\n" ); document.write( "h(5) = 400+55
\n" ); document.write( "h(5) = 455 feet
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