document.write( "Question 323282: A large pump can fill a 10,000 gallon tank 5 hours faster than a small pump. The large pump outputs water 100 gallons per hour faster than the small pump. Find the number of gallons pumped in 1 hour by each pump. \n" ); document.write( "
Algebra.Com's Answer #231410 by ankor@dixie-net.com(22740)\"\" \"About 
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A large pump can fill a 10,000 gallon tank 5 hours faster than a small pump.
\n" ); document.write( " The large pump outputs water 100 gallons per hour faster than the small pump.
\n" ); document.write( " Find the number of gallons pumped in 1 hour by each pump.
\n" ); document.write( ":
\n" ); document.write( "Let x = gal/hr of the smaller pump
\n" ); document.write( "(x+100) = gal/hr of the larger pump
\n" ); document.write( ":
\n" ); document.write( "small pump time - large pump time = 5 hrs
\n" ); document.write( "\"10000%2Fx\" - \"10000%2F%28x%2B100%29\" = 5
\n" ); document.write( "multiply by x(x+100), results
\n" ); document.write( "10000(x+100) - 10000x = 5x(x+100)
\n" ); document.write( ":
\n" ); document.write( "10000x + 1000000 - 10000x = 5x^2 + 500x
\n" ); document.write( "A quadratic equation
\n" ); document.write( "0 = 5x^2 + 500x - 1000000
\n" ); document.write( "Simplify, divide by 5
\n" ); document.write( "x^2 + 100x - 200000 = 0
\n" ); document.write( "Factors
\n" ); document.write( "(x + 500)(x - 400) = 0
\n" ); document.write( "x = 400 gal/hr, the rate of the small pump
\n" ); document.write( "and
\n" ); document.write( "400 + 100 = 500 gal/hr, the rate of the large pump
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution, find the time of each pump
\n" ); document.write( "10000/400 = 25 hrs
\n" ); document.write( "10000/500 = 20 hrs
\n" ); document.write( "---------------------
\n" ); document.write( "difference: 5 hrs
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