document.write( "Question 323282: A large pump can fill a 10,000 gallon tank 5 hours faster than a small pump. The large pump outputs water 100 gallons per hour faster than the small pump. Find the number of gallons pumped in 1 hour by each pump. \n" ); document.write( "
Algebra.Com's Answer #231410 by ankor@dixie-net.com(22740)    You can put this solution on YOUR website! A large pump can fill a 10,000 gallon tank 5 hours faster than a small pump. \n" ); document.write( " The large pump outputs water 100 gallons per hour faster than the small pump. \n" ); document.write( " Find the number of gallons pumped in 1 hour by each pump. \n" ); document.write( ": \n" ); document.write( "Let x = gal/hr of the smaller pump \n" ); document.write( "(x+100) = gal/hr of the larger pump \n" ); document.write( ": \n" ); document.write( "small pump time - large pump time = 5 hrs \n" ); document.write( " \n" ); document.write( "multiply by x(x+100), results \n" ); document.write( "10000(x+100) - 10000x = 5x(x+100) \n" ); document.write( ": \n" ); document.write( "10000x + 1000000 - 10000x = 5x^2 + 500x \n" ); document.write( "A quadratic equation \n" ); document.write( "0 = 5x^2 + 500x - 1000000 \n" ); document.write( "Simplify, divide by 5 \n" ); document.write( "x^2 + 100x - 200000 = 0 \n" ); document.write( "Factors \n" ); document.write( "(x + 500)(x - 400) = 0 \n" ); document.write( "x = 400 gal/hr, the rate of the small pump \n" ); document.write( "and \n" ); document.write( "400 + 100 = 500 gal/hr, the rate of the large pump \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution, find the time of each pump \n" ); document.write( "10000/400 = 25 hrs \n" ); document.write( "10000/500 = 20 hrs \n" ); document.write( "--------------------- \n" ); document.write( "difference: 5 hrs \n" ); document.write( "  |