document.write( "Question 323224: Find the distance between A and B, where A and B have the following coordinates:
\n" ); document.write( "A(–3, 5); B(5, –8). Show your work by using the notation sqrt( ) for square root.
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Algebra.Com's Answer #231375 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=-3\" and \"y%5B1%5D=5\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=5\" and \"y%5B2%5D=-8\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-3-5%29%5E2%2B%285--8%29%5E2%29\" Plug in \"x%5B1%5D=-3\", \"x%5B2%5D=5\", \"y%5B1%5D=5\", and \"y%5B2%5D=-8\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-8%29%5E2%2B%285--8%29%5E2%29\" Subtract \"5\" from \"-3\" to get \"-8\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-8%29%5E2%2B%2813%29%5E2%29\" Subtract \"-8\" from \"5\" to get \"13\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2864%2B%2813%29%5E2%29\" Square \"-8\" to get \"64\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2864%2B169%29\" Square \"13\" to get \"169\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28233%29\" Add \"64\" to \"169\" to get \"233\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=sqrt%28233%29\" \r
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\n" ); document.write( "\n" ); document.write( "Which approximates to \"d=15.264\" (using a calculator)\r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points A and B is exactly \"sqrt%28233%29\" units.\r
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\n" ); document.write( "\n" ); document.write( "and the approximate distance between the two points A and B is about 15.264 units.
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