document.write( "Question 37520: Can you help me find the linear equation and solution to this problem?\r
\n" ); document.write( "\n" ); document.write( "A river has a current of 2mph. Find the speed of Leroy's boat in still water if it goes 30 miles downstream in the same time it takes to go 18 miles upstream.\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "Alan
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Algebra.Com's Answer #23136 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The times for going upstream is the same as downstream
\n" ); document.write( "\"t%28u%29+=+t%28d%29\"
\n" ); document.write( "Time equals distance divided by rate
\n" ); document.write( "rate of the river = 2 mph
\n" ); document.write( "rate of boat going downstream = 2 + b
\n" ); document.write( "rate of boat going upstream = 2 - b
\n" ); document.write( "\"t%28u%29+=+18+%2F+%282+-+b%29\"
\n" ); document.write( "\"t%28d%29+=+30+%2F+%282+%2B+b%29\"
\n" ); document.write( "\"18+%2F+%282+-+b%29+=+30+%2F+%282+%2B+b%29\"
\n" ); document.write( "\"18%2A%282+%2B+b%29+=+30%2A%282+-+b%29\"
\n" ); document.write( "\"36+%2B+18b+=+60+-+30b\"
\n" ); document.write( "\"48b+=+24\"
\n" ); document.write( "\"b+=+1%2F2\"
\n" ); document.write( "Speed of boat in still water = 1/2 mph
\n" ); document.write( "check
\n" ); document.write( "\"18+%2F+%282+-+.5%29+=+30+%2F+%282+%2B+.5%29\"
\n" ); document.write( "\"18+%2F+1.5+=+30+%2F+2.5\"
\n" ); document.write( "\"180%2F15+=+300%2F25\"
\n" ); document.write( "\"12+=+12\"
\n" ); document.write( "checks
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