document.write( "Question 323156: What are two consecutive odd integers, such that six times the larger minus two times the smaller is 152? \n" ); document.write( "

Algebra.Com's Answer #231328 by QH(50) $\"\"$ $\"About$

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Assign variables to your integers.
\n" ); document.write( "The first (or smaller) will be X
\n" ); document.write( "Because they are consecutive ODD integers you will add 2 to the first integer to find the second.
\n" ); document.write( "So the second (larger) will be X+2
\n" ); document.write( "\"six times the larger minus two times the smaller is 152\" translates to
\n" ); document.write( "6(x+2)-2x=152
\n" ); document.write( "now solve for x using order of operations
\n" ); document.write( "6x+12-2x=152
\n" ); document.write( "4x+12=152
\n" ); document.write( "4x=140
\n" ); document.write( "x=35 so 35 is your first, smaller integer.
\n" ); document.write( "x+2=37 so 37 is your second, larger integer.
\n" ); document.write( "*check*
\n" ); document.write( "six times the larger minus two times the smaller is 152
\n" ); document.write( "6(37)-2(35)=152
\n" ); document.write( "222-70=152
\n" ); document.write( "152=152 \n" ); document.write( "

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